A) \[\frac{{{t}_{2}}}{{{t}_{1}}}={{\left( \frac{\sin {{\theta }_{1}}}{\sin {{\theta }_{2}}} \right)}^{1/2}}\]
B) \[\frac{{{t}_{2}}}{{{t}_{1}}}=1\]
C) \[\frac{{{t}_{2}}}{{{t}_{1}}}=\frac{\sin {{\theta }_{1}}}{\sin {{\theta }_{2}}}\]
D) \[\frac{{{t}_{2}}}{{{t}_{1}}}=\frac{{{\sin }^{2}}{{\theta }_{1}}}{{{\sin }^{2}}{{\theta }_{2}}}\]
Correct Answer: C
Solution :
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