A) \[N{{a}_{2}}S\]
B) \[S{{O}_{2}}\]
C) \[N{{a}_{2}}{{S}_{2}}{{O}_{3}}\]
D) \[{{H}_{2}}O\]
Correct Answer: B
Solution :
\[4S+6NaOH\xrightarrow{Boil}2N{{a}_{2}}S+N{{a}_{2}}{{S}_{2}}{{O}_{3}}+3{{H}_{2}}O\] Thus,\[S{{O}_{2}}\]is not produced when sulphur reacts with boiling\[NaOH\].
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