A) 50
B) 78.4
C) 80.0
D) 39.2
Correct Answer: A
Solution :
\[\underset{\begin{smallmatrix} (Ferrous\text{ }ammonium \\ \,\,\,\,\,\,\,\,\,\,\,\,sulphate) \end{smallmatrix}}{\mathop{{{N}_{1}}{{V}_{1}}}}\,=\underset{(KMn{{O}_{4}})}{\mathop{{{N}_{2}}{{V}_{2}}}}\,\] \[{{N}_{1}}\times 1000=\frac{1}{10}\times 50\] \[{{N}_{1}}=\frac{50}{{{10}^{4}}}=\frac{1}{200}\] Eq. wt. of \[FeS{{O}_{4}}.{{\text{(}N{{H}_{4}})}_{2}}S{{O}_{4}}.6{{H}_{2}}O\] =mol. wt.=392 \[\therefore \]Strength of pure salt \[=392\times \frac{1}{200}\] \[=1.96\,g\,{{L}^{-1}}\] \[\therefore \]% purity \[=\frac{1.96}{3.92}\times 100=50%\]
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