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BHU PMT BHU PMT (Mains) Solved Paper-2010

  • question_answer
    In hydrogen atom, energy of first excited state is\[-3.4\text{ }eV\]. Then find out the KE of the same orbit of hydrogen atom.

    A)  +3.4eV                                

    B)  +6.8eV

    C)  -13.6eV                              

    D)  +13.6eV

    Correct Answer: A

    Solution :

                     Energy in excited state is nothing but kinetic energy. Thus, KE of H-atom = + 3.4 eV


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