BHU PMT BHU PMT (Mains) Solved Paper-2010

  • question_answer
    An electron moving with velocity V is found to have a certain value of de-Broglie wavelength. The velocity to be possessed by the neutron to have the same de-Broglie wavelength is

    A)  \[\frac{1840}{v}\]                           

    B)  \[1840\,v\]

    C)   \[\frac{v}{1840}\]                          

    D)  \[v\]

    Correct Answer: C

    Solution :

                     \[{{\lambda }_{e}}=\frac{h}{{{m}_{e}}{{v}_{e}}},{{\lambda }_{m}}=\frac{h}{{{m}_{n}}{{v}_{n}}}\]As\[{{\lambda }_{e}}={{\lambda }_{n}},\] \[\frac{1}{{{m}_{e}}{{v}_{e}}}=\frac{1}{{{m}_{n}}{{v}_{n}}}\]or\[\frac{{{v}_{n}}}{{{v}_{e}}}=\frac{{{m}_{e}}}{{{m}_{n}}}=\frac{1}{1840}\]                 Or           \[{{v}_{n}}=\frac{{{v}_{e}}}{1840}\]


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