Directions : In the following question more than one of the answers given may be correct. Select the correct answer and mark it according to the code:
When some potential difference is maintained between A and B, current i enters the network at A and leaves at B as shown in the figure. Then (1) The equivalent resistance between A and B is\[8\,\Omega \]. (2) C and D are at the same potential (3) Current\[\frac{3i}{5}\]flows from D to C (4) No current flows between C and DA) 1, 2 and 3 are correct
B) 1 and 2 are correct
C) 2 and 4 are correct
D) 1 and 3 are correct
Correct Answer: A
Solution :
The equivalent resistance between points A and B is \[{{R}_{eq}}=\frac{20\times 5}{20+5}+\frac{5\times 20}{5+20}\] \[{{R}_{eq}}=8\,\Omega \] C and D are joined, they must be at the same potential. \[{{V}_{A}}-{{V}_{C}}={{V}_{A}}-{{V}_{D}}\] \[20{{i}_{1}}=5(i-{{i}_{1}})\] \[{{i}_{1}}=\frac{i}{5}\] Current flowing from D to C is \[i-2{{i}_{1}}=i-\frac{2i}{5}=\frac{3i}{5}\] Hence, option is correct.You need to login to perform this action.
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