A) \[\frac{\Delta H}{nF}\]
B) \[\frac{\Delta G}{nF}\]
C) \[\frac{\Delta S}{nF}\]
D) \[\frac{-\Delta S}{nF}\]
Correct Answer: C
Solution :
\[\Delta G=\Delta H-T\Delta S\] \[\Delta G=\Delta H+T{{\left[ \frac{d(\Delta G)}{dT} \right]}_{p}}\] On comparing the above two equations, we get \[\Delta S=\frac{-d(\Delta G)}{dT}\] \[\Delta S=\frac{-d(-FE)}{dT}\] \[[\because \Delta G=-nFE]\] \[\Delta S=\frac{+dnFE}{dT}\] \[=nF\frac{dE}{dt}\] \[\Rightarrow \] \[\frac{dE}{dt}=\frac{\Delta S}{nF}\]You need to login to perform this action.
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