A) 4.5V
B) 9V
C) zero
D) 2V
Correct Answer: C
Solution :
\[OA=\sqrt{{{(\sqrt{2})}^{2}}+{{(\sqrt{2})}^{2}}}\] \[OA=2={{r}_{1}}\] and \[OB=2={{r}_{2}}\] The potential difference between the point A and B will be \[{{V}_{A}}-{{V}_{B}}=\frac{q}{4\pi {{\varepsilon }_{0}}{{r}_{1}}}-\frac{q}{4\pi {{\varepsilon }_{0}}{{r}_{2}}}\] \[{{V}_{A}}-{{V}_{B}}=0\](zero)You need to login to perform this action.
You will be redirected in
3 sec