A) 32
B) 16
C) 1
D) 64
Correct Answer: D
Solution :
The moment of inertia of\[X\] \[{{I}_{X}}=\frac{1}{2}{{M}_{X}}{{R}^{2}}\] Mass of\[X\]plate\[=volume\times density\] \[{{M}_{X}}=(\pi {{R}^{2}}t)\rho \] \[\therefore \] \[{{I}_{X}}=\frac{1}{2}(\pi {{R}^{2}}t)\rho {{R}^{2}}\] The moment of inertia of Y \[{{I}_{Y}}=\frac{1}{2}{{M}_{y}}(4{{R}^{2}})\] Mass of\[y\]plate \[=volume\times density\] \[{{M}_{Y}}=(\pi {{(4R)}^{2}}t)\rho \] \[\therefore \] \[{{I}_{Y}}=\frac{1}{2}(\pi 16{{R}^{2}}\frac{t}{4}\rho )16{{R}^{2}}\] The ratio of moments of inertia \[\frac{{{I}_{Y}}}{{{I}_{X}}}=64\]You need to login to perform this action.
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