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BHU PMT BHU PMT (Mains) Solved Paper-2011

  • question_answer
    A dip needle lies initially in the magnetic meridian when it shows an angle of dip\[\theta \]at a place. The dip circle is rotated through an angle\[x\]in the vertical plane and then it shows an angle of dip\[\theta '\].Then\[\frac{\tan \theta '}{\tan \theta }\]is

    A)  \[\frac{1}{\cos x}\]                        

    B)  \[\frac{1}{\sin x}\]

    C)  \[\frac{1}{\tan x}\]                        

    D)  \[\cos x\]

    Correct Answer: A

    Solution :

                     In magnetic meridian, angle of dip is given by \[\tan \theta =\frac{V}{H}\]                                        ...(i) When dip circle is rotated in vertical plane, then \[\tan \theta '=\frac{V}{H\cos x}\] \[\therefore \]  \[\frac{\tan \theta '}{\tan \theta }=\frac{1}{\cos x}\]


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