2. Solved Papers
  3. BHU PMT

BHU PMT BHU PMT (Mains) Solved Paper-2011

  • question_answer
    Two masses of 10 kg and 20 kg respectively are tied together by a massless spring. A force of 200 N is applied on a 20 kg mass as shown in figure. At the instant shown the acceleration of 10 kg mass is\[12\text{ }m/{{s}^{2}},\] the acceleration of 20 kg mass is

    A)  zero                                     

    B) \[10\text{ }m/{{s}^{2}}\]

    C)  \[4\text{ }m/{{s}^{2}}\]               

    D) \[12\text{ }m/{{s}^{2}}\]

    Correct Answer: C

    Solution :

                     Force on the block of 10 kg \[=ma=10\times 12=120N\] The total force applied = 200 N The force acting on block of 20 kg \[=200-120=80\text{ }N\] The acceleration of block of 20 kg                                 \[=\frac{80}{20}=4\,m/{{s}^{2}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner