A) \[59{}^\circ \]
B) \[118{}^\circ \]
C) \[177{}^\circ \]
D) \[236{}^\circ \]
Correct Answer: D
Solution :
Wavelength of waves\[\lambda =\frac{v}{n}\] \[=\frac{330}{540}=\frac{11}{18}m\] Path difference between the waves, \[\Delta x=4.4\text{ }m-4\text{ }m\] \[=0.4\text{ }m\] Phase difference\[=\frac{2\pi }{\lambda }\times \] path difference \[\therefore \] \[\Delta \phi =\frac{2\pi }{11/18}\times 0.4=\frac{14.4}{11}\pi \]rad \[=\frac{14.4\pi }{11}\times \frac{{{360}^{o}}}{2\pi }\] \[\simeq {{360}^{o}}\]
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