BHU PMT BHU PMT (Mains) Solved Paper-2011

  • question_answer
    5 beat/s are produced on blowing together two closed organ pipes of same diameter but of different lengths. If shorter pipes is of 10 cm length and speed of sound m air is 300 m/s, length of other pipe is

    A)  10.06 cm            

    B)  11.22 cm

    C)  16 cm                                  

    D)  14 cm

    Correct Answer: A

    Solution :

                     \[m-{{n}_{1}}-{{n}_{2}}=\frac{v}{4}\left[ \frac{1}{{{l}_{1}}}-\frac{1}{{{l}_{2}}} \right]\] \[5=\frac{300\times 100}{4}\left[ \frac{1}{{{l}_{1}}}-\frac{1}{{{l}_{2}}} \right]\] \[\frac{1}{{{l}_{1}}}-\frac{1}{{{l}_{2}}}=\frac{20}{300\times 120}=\frac{1}{1500}\] \[\frac{1}{{{l}_{2}}}=\frac{1}{10}-\frac{1}{1500}=\frac{149}{1500}\] \[\Rightarrow \]               \[{{l}_{2}}=10.06\,cm\]


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