A) 12s
B) 24s
C) 30s
D) 36s
Correct Answer: B
Solution :
\[x=-\frac{1}{3}{{t}^{2}}+16t+3\] Velocity, \[v=\frac{dx}{dt}\] \[=\frac{d}{dt}\left( -\frac{1}{3}{{t}^{2}}+16t+3 \right)\] \[=-\frac{2}{3}t+16\] The body comes to rest, so\[v=0\] i.e., \[-\frac{2}{3}t+16=0\] \[\Rightarrow \] \[\frac{2}{3}t=16\] \[t=\frac{16\times 3}{2}\] \[=24\,s\]You need to login to perform this action.
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