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BHU PMT BHU PMT (Mains) Solved Paper-2011

  • question_answer
    The ionization constant of a weak electrolyte is\[25\times {{10}^{-6}}\] while the equivalent conductance of its 0.01 M solution is\[19.6\text{ }S\text{ }c{{m}^{2}}e{{q}^{-1}}\]. The equivalent conductance of the electrolyte at infinite dilution (in\[S\text{ }c{{m}^{2}}e{{q}^{-1}}\]) will be

    A)  340                                       

    B)  208

    C)   364                                      

    D)  392

    Correct Answer: D

    Solution :

    Sol.         \[\underset{\begin{smallmatrix}  \,\,\,\,\,\,C \\  C(1-\alpha ) \end{smallmatrix}}{\mathop{HA}}\,\underset{\begin{smallmatrix}  \,\,0 \\  C\alpha  \end{smallmatrix}}{\mathop{{{H}^{+}}}}\,+\underset{\begin{smallmatrix}  \,\,\,0 \\  C\alpha  \end{smallmatrix}}{\mathop{{{A}^{-}}}}\,\] \[K=\frac{C.\alpha .C\alpha }{C(1-\alpha )}=\frac{C{{\alpha }^{2}}}{1-\alpha }\simeq C{{\alpha }^{2}}\] \[25\times {{10}^{-6}}={{10}^{-2}}\times {{\alpha }^{2}}\] \[\alpha =5\times {{10}^{-2}}\]                 \[\alpha =\frac{{{\Lambda }^{c}}}{{{\Lambda }^{\infty }}}\] \[{{\Lambda }^{\infty }}=\frac{{{\Lambda }^{c}}}{\alpha }=\frac{19.6}{5\times {{10}^{2}}}=382S\,c{{m}^{2}}e{{q}^{-1}}\]


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