A) \[M\]
B) \[\frac{M}{2}\]
C) \[\frac{M}{5}\]
D) \[\frac{M}{6}\]
Correct Answer: D
Solution :
Sol. \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}+4{{H}_{2}}S{{O}_{4}}\xrightarrow{{}}\] \[{{K}_{2}}S{{O}_{4}}+C{{r}_{2}}{{(S{{O}_{4}})}_{3}}+4{{H}_{2}}O+3[O]\] or\[C{{r}_{2}}O_{7}^{2-}+14{{H}^{+}}+6{{e}^{-}}\xrightarrow{{}}2C{{r}^{3+}}+7{{H}_{2}}O\] Equivalent weight of \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}=\frac{molecular\text{ }mass}{6}\]
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