A) 340
B) 208
C) 364
D) 392
Correct Answer: D
Solution :
Sol. \[\underset{\begin{smallmatrix} \,\,\,\,\,\,C \\ C(1-\alpha ) \end{smallmatrix}}{\mathop{HA}}\,\underset{\begin{smallmatrix} \,\,0 \\ C\alpha \end{smallmatrix}}{\mathop{{{H}^{+}}}}\,+\underset{\begin{smallmatrix} \,\,\,0 \\ C\alpha \end{smallmatrix}}{\mathop{{{A}^{-}}}}\,\] \[K=\frac{C.\alpha .C\alpha }{C(1-\alpha )}=\frac{C{{\alpha }^{2}}}{1-\alpha }\simeq C{{\alpha }^{2}}\] \[25\times {{10}^{-6}}={{10}^{-2}}\times {{\alpha }^{2}}\] \[\alpha =5\times {{10}^{-2}}\] \[\alpha =\frac{{{\Lambda }^{c}}}{{{\Lambda }^{\infty }}}\] \[{{\Lambda }^{\infty }}=\frac{{{\Lambda }^{c}}}{\alpha }=\frac{19.6}{5\times {{10}^{2}}}=382S\,c{{m}^{2}}e{{q}^{-1}}\]You need to login to perform this action.
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