Directions : In the following question more than one of the answers given may be correct. Select the correct answer and mark it according to the code:
When\[C{{l}_{2}}\]is passed through hot\[NaOH,\] oxidation number of\[Cl\]changes from (1) 0 to + 5 (2) -1 to 0 (3) 0 to -1 (4) 0 to + 7A) 1, 2 and 3 are correct
B) 1 and 2 are correct
C) 2 and 4 are correct
D) 1 and 3 are correct
Correct Answer: D
Solution :
\[\overset{0}{\mathop{3C{{l}_{2}}}}\,+6NaOH\xrightarrow{{}}\overset{+1}{\mathop{5NaCl}}\,+\overset{+5}{\mathop{NaCl{{O}_{3}}}}\,+3{{H}_{2}}O\] Hence, Oxidation number of\[Cl\]changes from 0 to- 1 and 0 to +5.
You need to login to perform this action.
You will be redirected in
3 sec
