A) 2T
B) 4T
C) \[{{(2)}^{1/2}}T\]
D) \[2{{(2)}^{1/2}}T\]
Correct Answer: C
Solution :
From gas equation we have \[PV=RT\]where R is gas constant. Also given \[P{{V}^{3/2}}=\] constant \[\therefore \]Putting the value of \[P=\frac{RT}{V},\]we have \[\frac{RT}{V}{{V}^{3/2}}=\]constant \[T{{V}^{1/2}}=\]constant \[{{T}_{1}}V_{1}^{1/2}={{T}_{2}}V_{2}^{1/2}\] Given, \[{{T}_{1}}=T,{{V}_{1}}=V,{{V}_{2}}=\frac{V}{2'}\] \[\therefore \] \[T{{V}^{1/2}}={{T}_{2}}{{\left( \frac{V}{2} \right)}^{1/2}}\] \[\Rightarrow \] \[{{T}_{2}}={{(2)}^{1/2}}T\]You need to login to perform this action.
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