A) both square planar
B) tetrahedral and square planar respectively
C) both tetrahedral
D) square planar and tetrahedral respectively
Correct Answer: C
Solution :
\[Ni{{(CO)}_{4}}-\]Oxidation state of\[Ni=0\]. Oxidation state of\[Ni\]in\[Ni{{(PP{{h}_{3}})}_{2}}C{{l}_{2}}\]is \[x+0\times 2+(-2)=0\] \[\therefore \] \[x=+2\]You need to login to perform this action.
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