A) 8r
B) 2r
C) 4r
D) \[2\sqrt{2}r\]
Correct Answer: C
Solution :
From Bohr's theory of atom, we have if e, m be the charge and mass of electron, Z be the atomic number, then radius of nth Bohr orbit is \[r={{n}^{2}}\frac{{{h}^{2}}{{\varepsilon }_{o}}}{\pi mZ{{e}^{z}}}\] \[\Rightarrow \] \[r={{n}^{2}}\] For \[n=2\] \[{{r}_{2}}={{(2)}^{2}}r=4r\]You need to login to perform this action.
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