A) 12.1 h
B) 9.7 h
C) 11.3 h
D) 1.8 h
Correct Answer: C
Solution :
Key Idea: The half-life period and rate constant of reaction are related as follows \[{{t}_{1/2}}=\frac{0.693}{k}\] Given,\[k=1.7\times {{10}^{-5}}{{s}^{-1}}\] \[\therefore \] \[{{t}_{1/2}}=\frac{0.693}{1.7\times {{10}^{-5}}}\] \[=0.41\times {{10}^{5}}s\] \[=\frac{0.41\times {{10}^{5}}}{60\times 60}h\] \[=11.3h\]You need to login to perform this action.
You will be redirected in
3 sec