A) \[[Ar]3{{d}^{6}}\,4{{s}^{2}}\]
B) \[[Ar]3{{d}^{5}}\,4{{s}^{2}}\]
C) \[[Ar]3{{d}^{4}}\,4{{s}^{2}}\]
D) \[[Ar]\,3{{d}^{5}}\,4{{s}^{1}}\]
Correct Answer: D
Solution :
The correct electronic configuration of Cr is \[[Ar]\text{ }3{{d}^{5}},4{{s}^{1}}\]and not\[[Ar]\text{ }3{{d}^{4}},4{{s}^{2}}\]because exactly half filled and exactly full filled orbitals are more stable than nearly half filled and nearly full filled orbitals.
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