A) passing ethanol over heated alumina
B) heating sodium ethoxide with ethyl bromide
C) treating ethyl alcohol with excess of \[{{H}_{2}}S{{O}_{4}}\]at 430-440 K
D) heating ethanol with dry\[A{{g}_{2}}O\]
Correct Answer: B
Solution :
All the reactions given as choices , and are different methods of preparation of ethoxyethane but only the following is called Williamson synthesis. Williamson synthesis \[\underset{sod.\,ethoxide}{\mathop{{{C}_{2}}{{H}_{5}}ONa}}\,+\underset{Ethyl\,bromide}{\mathop{{{C}_{2}}{{H}_{5}}Br}}\,\xrightarrow{{}}\] \[\underset{Ethoxy\text{ }ethane}{\mathop{{{C}_{2}}{{H}_{5}}-O-{{C}_{2}}{{H}_{5}}+NaBr}}\,\] \[{{C}_{2}}{{H}_{5}}OH\xrightarrow[{}]{A{{l}_{2}}{{O}_{3}}}{{C}_{2}}{{H}_{5}}O{{C}_{2}}{{H}_{5}}\] \[{{C}_{2}}{{H}_{5}}OH\xrightarrow[\Delta 430-440]{{{H}_{2}}S{{o}_{4}}}{{C}_{2}}{{H}_{5}}O{{C}_{2}}{{H}_{5}}\] \[{{C}_{2}}{{H}_{5}}OH\xrightarrow[{}]{A{{g}_{2}}O}{{C}_{2}}{{H}_{5}}O{{C}_{2}}{{H}_{5}}\] Above , and are the methods of preparing ethoxy ethane but not the Williamson's synthesis method.
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