A) \[F{{e}^{3+}}\]
B) \[F{{e}^{2+}}\]
C) \[C{{o}^{2+}}\]
D) \[C{{o}^{3+}}\]
Correct Answer: A
Solution :
Electronic configuration of ions is as follows: \[F{{e}^{3+}}\,1{{s}^{2}},2{{s}^{2}},2{{p}^{6}},3{{s}^{2}},3{{p}^{6}}4{{s}^{0}},3{{d}^{5}}\] \[\therefore \]5 unpaired electrons \[F{{e}^{2+}}~~1{{s}^{2}},\text{ }2{{s}^{2}},\text{ }2{{p}^{6}},\text{ }3{{s}^{2}},\text{ }3{{p}^{6}}\text{ }4{{s}^{0}},\text{ }3{{d}^{6}}\] \[\therefore \]4 unpaired electrons \[C{{o}^{2+}}\,\,\,1{{s}^{2}},2{{s}^{2}},2{{p}^{6}},3{{s}^{2}},3{{p}^{6}}4{{s}^{0}},3{{d}^{7}}\] \[\therefore \]3 unpaired electrons \[C{{o}^{3+}}~~1{{s}^{2}},\text{ }2{{s}^{2}},\text{ }2{{p}^{6}},\text{ }3{{s}^{2}},\text{ }3{{p}^{6}}\text{ }4{{s}^{0}},\,3{{d}^{6}}\] \[\therefore \]4 unpaired electrons \[\therefore \]\[F{{e}^{3+}}\]has 5 unpaired electrons.
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