BHU PMT BHU PMT (Screening) Solved Paper-2005

  • question_answer
    The light rays having photons of energy 1.8 eV are falling on a metal surface having a work function 1.2eV. What is the stopping potential to be applied to stop the emitting electrons?

    A)  3eV                                      

    B)  1.2eV

    C)  0.6V                                     

    D)  1.4V

    Correct Answer: C

    Solution :

                      Key Idea: Stopping  potential stops  the maximum kinetic energy electrons. From Einstein's photoelectric equation, we have                 \[{{E}_{k}}=hv-W\] where hv is energy of photon absorbed by the electron in the metal, W is the work function of the metal. Also the potential at which the photoelectric current becomes zero is called Stopping potential or cut-off potential. Since, the stopping potential stops the maximum energy electrons, it is a measure of the maximum kinetic energy of the electrons. Given,   \[hv=1.8eV,\text{ }W=1.2eV\] \[\therefore \]  \[{{E}_{k}}=1.8-1.2=0.6\,eV\] Thus, stopping potential                 \[=\frac{{{E}_{k}}}{e}=\frac{0.6\times 1.6\times {{10}^{-19}}}{1.6\times {{10}^{19}}}\] \[=0.6V\]


You need to login to perform this action.
You will be redirected in 3 sec spinner