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BHU PMT BHU PMT (Screening) Solved Paper-2005

  • question_answer
    The equivalent weight of phosphoric acid\[({{H}_{3}}P{{O}_{4}})\]in the reaction: \[NaOH+{{H}_{2}}P{{O}_{4}}\xrightarrow{{}}Na{{H}_{2}}P{{O}_{4}}+{{H}_{2}}O\]is:

    A)  59                                         

    B)  49     

    C)  25                                         

    D)  98

    Correct Answer: D

    Solution :

                     \[\underset{\begin{smallmatrix}  23+16+1 \\  =40  \\  1g.eq \end{smallmatrix}}{\mathop{NaOH}}\,+\underset{\begin{smallmatrix}  1\times 3+31+16\times 4 \\  =98  \\  1g-eq \end{smallmatrix}}{\mathop{{{H}_{3}}P{{O}_{4}}}}\,\xrightarrow[{}]{{}}Na{{H}_{2}}P{{O}_{4}}+{{H}_{2}}O\] \[\therefore \]equivalent weight of\[{{H}_{3}}P{{O}_{4}}\]is 98 g In the above reaction no change in oxidation state of phosphorus takes place. So, equivalent weight will by equal to its molecular weight.


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