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BHU PMT BHU PMT (Screening) Solved Paper-2006

  • question_answer
    A body moves along a circular path of radius 10 m and the coefficient of friction is 0.5. What should be its angular speed in rad/s if it is not to slip from the surface? (\[g=9.8\text{ }m{{s}^{-2}}\])

    A)  5                                            

    B)  10  

    C)  0.1                                        

    D)  0.7

    Correct Answer: D

    Solution :

                     Key Idea: The necessary centripetal force to the coin is provided by the frictional force. For moving on circular path without slipping, centripetal force must equal frictional force. That is,                 \[\frac{m{{v}^{2}}}{r}=\mu mg\] Or           \[mr{{\omega }^{2}}=\mu mg\]                \[(\therefore v=r\omega )\] Or           \[r{{\omega }^{2}}=\mu g\]


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