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BHU PMT BHU PMT (Screening) Solved Paper-2006

  • question_answer
    Young's modulus of the material of a wire is Y. On pulling the wire by a force F, the increase in its length is x. The potential energy of the stretched wire is:

    A)  \[\frac{1}{2}Fx\]                             

    B)  \[\frac{1}{2}Yx\]

    C)   \[\frac{1}{2}F{{x}^{2}}\]                             

    D)  none of these

    Correct Answer: A

    Solution :

                     When a wire is stretched through a length, then work has to be done, this work is stored in the wire in the form of elastic potential energy. Potential energy of stretched wire is \[U=\frac{1}{2}\times stress\times strain\] \[\therefore \]  \[U=\frac{1}{2}\times F\times x\] \[\Rightarrow \]               \[U=\frac{1}{2}Fx\]        


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