A) Zero
B) \[2\text{ }m/{{s}^{2}}\]
C) \[1.5\text{ }m/{{s}^{2}}\]
D) 5 m/s
Correct Answer: A
Solution :
We can realise the situation as shown. Maximum retadation. \[a=\frac{{{f}_{k}}-mg\sin \theta }{m}\] \[=\frac{{{u}_{k}}mg\cos \theta -mg\sin \theta }{m}\] \[=\frac{\frac{1}{\sqrt{3}}mg\cos {{30}^{o}}-mg\sin {{30}^{o}}}{m}(\theta ={{30}^{o}})\] \[=\frac{\frac{1}{\sqrt{3}}g\times \frac{\sqrt{3}}{2}-g\times \frac{1}{2}}{1}\] \[=0\] Hence, under the effect of kinetic friction between, block and inclined plane, acceleration of block is zero.You need to login to perform this action.
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