BHU PMT BHU PMT (Screening) Solved Paper-2006

  • question_answer
    A bar magnet has a coercively\[4\times {{10}^{3}}A{{m}^{-1}}\]. It is desired to demagnetize it by inserting it inside a solenoid 12 cm long and having 60 turns. The current carried by the solenoid should be:

    A)  8 A                                        

    B)  6 A

    C)  4.5 A                                    

    D)  2 A

    Correct Answer: A

    Solution :

                     The reversed magnetic field needed to demagnetise the specimen is known as coercivity of the material. \[B={{\mu }_{0}}H\] or            \[{{\mu }_{0}}ni={{\mu }_{0}}H\] or            \[\frac{Ni}{L}=H\]                            \[\left( \because n=\frac{N}{L} \right)\] or            \[i=\frac{HL}{N}\] Given,   \[H=4\times {{10}^{3}}A{{m}^{-1}},\] \[L=12\text{ }cm=12\times {{10}^{-2}}m,\text{ }N=60\text{ }turns\]. Substituting the values, we get                 \[i=\frac{4\times {{10}^{3}}\times 12\times {{10}^{-2}}}{60}=8A\]


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