BHU PMT BHU PMT (Screening) Solved Paper-2006

  • question_answer
    Frequencies higher than 10 MHz were found not being reflected by the ionosphere on a particular day at a place. The maximum electron density of the ionosphere on the day was near to:

    A)  \[1.5\times {{10}^{10}}{{m}^{-3}}\]        

    B) \[1.24\times {{10}^{12}}{{m}^{-3}}\]

    C)  \[3\times {{10}^{12}}{{m}^{-3}}\]           

    D)  none of these

    Correct Answer: B

    Solution :

                     The value of maximum frequency\[f\]which can be reflected from the layer at an angle of incidence i is given by \[{{f}^{2}}=\frac{80.6N}{{{\cos }^{2}}i}\] where\[i\]is angle of incidence and N is electron density. For the wave not reflected from ionosphere,\[i=0\] \[\therefore \]  \[{{f}^{2}}=\frac{80.6N}{{{\cos }^{2}}{{0}^{o}}}=80.6\,N\] Or           \[N=\frac{{{f}^{2}}}{80.6}=\frac{{{(10\times {{10}^{6}})}^{2}}}{80.6}\] \[=1.24\times {{10}^{12}}per\,\,{{m}^{-3}}\]


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