A) \[7{}^\circ C\]
B) \[65{}^\circ C\]
C) \[63{}^\circ \text{ }C\]
D) \[35{}^\circ C\]
Correct Answer: D
Solution :
The relation between Celsius scale and Fahrenheit scale is as derived below: 100 parts of Celsius scale = 180 parts of Fahrenheit scale \[\therefore \]1 part of Celsius scale\[=\frac{9}{5}\]parts of Fahrenheit scale Hence, \[{{T}_{F}}=32+\frac{9}{5}{{T}_{C}}\] Or \[{{T}_{C}}=\frac{5}{9}({{T}_{F}}-32)\] Given, \[{{T}_{F}}={{95}^{o}}F\] \[\therefore \] \[{{T}_{C}}=\frac{5}{9}(95-32)\] \[={{35}^{o}}C\]You need to login to perform this action.
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