BHU PMT BHU PMT (Screening) Solved Paper-2006

  • question_answer
    In hydrogen atom, the electron is moving round the nucleus with velocity\[2.18\times {{10}^{6}}\] m/s in an orbit of radius \[0.528\overset{\text{o}}{\mathop{\text{A}}}\,\]. The acceleration of the electron is:

    A)  \[9\times {{10}^{18}}m/{{s}^{2}}\]         

    B) \[9\times {{10}^{22}}m/{{s}^{2}}\]

    C)  \[9\times {{10}^{-22}}m/{{s}^{2}}\]       

    D) \[9\times {{10}^{-12}}m/{{s}^{2}}\]

    Correct Answer: B

    Solution :

    The electron in a hydrogen atom, moves with constant acceleration, called centripetal acceleration, round the nucleus. Acceleration of electron \[a=\frac{{{v}^{2}}}{r}\] Given,      \[v=2.18\times {{10}^{6}}m/s,\] \[r=0.528\overset{\text{o}}{\mathop{\text{A}}}\,=0.528\times {{10}^{-10}}m\]               \[\therefore \]  \[a=\frac{(2.18\times {{10}^{6}})}{0.528\times {{10}^{-10}}}=9\times {{10}^{-10}}m/{{s}^{2}}\]


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