question_answer

If boiling point of water is\[95{}^\circ F,\]what will be reduction at Celsius scale?

A) \[7{}^\circ C\]                                   

B) \[65{}^\circ C\]

C) \[63{}^\circ \text{ }C\]                                  

D) \[35{}^\circ C\]

Correct Answer: D

Solution :

                 The relation between Celsius scale and Fahrenheit scale is as derived below: 100 parts of Celsius scale = 180 parts of   Fahrenheit scale \[\therefore \]1 part of Celsius scale\[=\frac{9}{5}\]parts of  Fahrenheit scale Hence,                  \[{{T}_{F}}=32+\frac{9}{5}{{T}_{C}}\] Or           \[{{T}_{C}}=\frac{5}{9}({{T}_{F}}-32)\] Given,      \[{{T}_{F}}={{95}^{o}}F\] \[\therefore \]  \[{{T}_{C}}=\frac{5}{9}(95-32)\]                 \[={{35}^{o}}C\]