A) \[9\times {{10}^{18}}m/{{s}^{2}}\]
B) \[9\times {{10}^{22}}m/{{s}^{2}}\]
C) \[9\times {{10}^{-22}}m/{{s}^{2}}\]
D) \[9\times {{10}^{-12}}m/{{s}^{2}}\]
Correct Answer: B
Solution :
The electron in a hydrogen atom, moves with constant acceleration, called centripetal acceleration, round the nucleus. Acceleration of electron \[a=\frac{{{v}^{2}}}{r}\] Given, \[v=2.18\times {{10}^{6}}m/s,\] \[r=0.528\overset{\text{o}}{\mathop{\text{A}}}\,=0.528\times {{10}^{-10}}m\] \[\therefore \] \[a=\frac{(2.18\times {{10}^{6}})}{0.528\times {{10}^{-10}}}=9\times {{10}^{-10}}m/{{s}^{2}}\]You need to login to perform this action.
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