A) 0.56 cm
B) 1.35 cm
C) 0.41 cm
D) 2.32 cm
Correct Answer: C
Solution :
Key Idea: At the same level in the two limbs of the U-tube, pressure is same. On pouring water on the left side, mercury rises \[x\]cm (say) from its previous level in the right limb of \[U-\]tube creating a difference of levels of mercury by\[2xcm\]. Equating pressures at AB, we get \[{{P}_{A}}={{P}_{B}}\] \[\therefore \]\[11.2\times {{10}^{-2}}\times {{\rho }_{water}}\times g\] \[=2x\times {{\rho }_{mercury}}\times g\] \[11.2\times {{10}^{-2}}\times 1000\,kg/{{m}^{3}}\] \[=2x\times 13600\,kg/{{m}^{3}}\] \[\therefore \]\[x=\frac{11.2\times {{10}^{-2}}\times 1000}{2\times 13600}m=0.41\,cm\]You need to login to perform this action.
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