A) 0.8g/cc
B) 1.2g/cc
C) 1.4 g/cc
D) 1.6 g/cc
Correct Answer: A
Solution :
As shown in figure, in the two arms of a tube pressure remains same on surface PP'. Hence, \[8\times {{\rho }_{\gamma }}\times g+2\times {{\rho }_{Hg}}\times g=10\times {{\rho }_{\gamma }}\times g\] \[\therefore \] \[8{{\rho }_{\gamma }}+2\times 13.6=10\times 3.36\] Or \[{{\rho }_{\gamma }}=\frac{33.6-27.2}{8}=0.8\,g/cc\]You need to login to perform this action.
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