A) \[NaHC{{O}_{3}}\]
B) Tollen's reagent
C) \[NaOH\]
D) none of these
Correct Answer: B
Solution :
Formic acid can be distinguished from acetic acid by Tollen's reagent. HCOOH reduces Tollen's reagent into metallic silver while acetic acid does not give this test. \[HCOOH+A{{g}_{2}}O\xrightarrow{\Delta }\underset{silver\,mirror}{\mathop{2Ag+}}\,C{{O}_{2}}+{{H}_{2}}O\]
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