BHU PMT BHU PMT (Screening) Solved Paper-2006

  • question_answer
    Which pair is of isoelectronic species?

    A)  \[{{K}^{+}},C{{l}^{-}},N{{a}^{+}}\]           

    B)  \[{{K}^{+}},C{{l}^{-}},C{{a}^{2+}}\]

    C)   \[{{F}^{-}},A{{l}^{3+}},{{K}^{+}}\]           

    D)  \[F{{e}^{2+}},C{{u}^{2+}},{{V}^{3+}}\]

    Correct Answer: B

    Solution :

                     Isoelectronic species have same number of electrons. \[{{K}^{+}}\]number of electrons =18 \[C{{l}^{-}}\]number of electrons = 18 \[C{{a}^{2+}}\]number of electrons = 18 Hence,\[{{K}^{+}},C{{l}^{-}}\]and\[C{{a}^{2+}}\]are isoelectronic species.


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