A) 10
B) 5
C) 8
D) 32
Correct Answer: C
Solution :
Suppose the number of a-particles emitted\[=x\]and number of P-particles emitted = y then\[_{92}{{U}^{238}}{{\xrightarrow{{}}}_{82}}P{{b}^{206}}+{{x}_{2}}{{\alpha }^{4}}+{{y}_{-1}}{{\beta }^{0}}\] Equating the mass number on both sides, we get \[238=206+4x+0y\]or \[4x=32\] or \[x=\frac{32}{4}=8\] Hence,\[8\alpha -\]particles will be emitted.You need to login to perform this action.
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