A) 5
B) 10
C) 0.1
D) 0.7
Correct Answer: D
Solution :
Key Idea: The necessary centripetal force to the coin is provided by the frictional force. For moving on circular path without slipping, centripetal force must equal frictional force. That is, \[\frac{m{{v}^{2}}}{r}=\mu mg\] Or \[mr{{\omega }^{2}}=\mu mg\] \[(\therefore v=r\omega )\] Or \[r{{\omega }^{2}}=\mu g\]You need to login to perform this action.
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