A) \[{{H}_{2}}S{{O}_{4}}\]
B) \[KMnS{{O}_{4}}\]
C) Oxalic acid
D) \[MnS{{O}_{4}}\]
Correct Answer: D
Solution :
\[MnS{{O}_{4}}\]acts as auto catalyst during the titration of\[KMn{{O}_{4}}\]and oxalic acid in presence of \[{{H}_{2}}S{{O}_{4}}.Mn{{O}_{4}}\]is formed during the reaction. \[5{{H}_{2}}{{C}_{2}}{{O}_{4}}+2KMn{{O}_{4}}+3{{H}_{2}}S{{O}_{4}}\xrightarrow{{}}2MnS{{O}_{4}}\] \[+{{K}_{2}}S{{O}_{4}}+10C{{O}_{2}}+8{{H}_{2}}O\]
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