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BHU PMT BHU PMT (Screening) Solved Paper-2006

  • question_answer
    If the solubility of\[Pb{{I}_{2}}\]in its saturated solutions at\[25{}^\circ C\]be\[2\times {{10}^{-3}}\] mol/L. Its solubility product is:

    A)  \[4\times {{10}^{-9}}\]                                 

    B) \[8\times {{10}^{-12}}\]

    C)   \[6\times {{10}^{-9}}\]                                

    D) \[32\times {{10}^{-9}}\]

    Correct Answer: D

    Solution :

                     \[Pb{{I}_{2}}P{{b}^{2+}}+2{{I}^{-}}\] \[{{K}_{sp}}=4{{x}^{3}}\]                 \[=4{{(2\times {{10}^{-3}})}^{3}}\] \[{{K}_{sp}}=32\times {{10}^{-9}}\]


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