A) Ionic bond
B) Covalent bond
C) Co-ordinate bond
D) All of the above
Correct Answer: B
Solution :
Electronic configuration of\[_{16}{{S}^{32}}=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{4}}\]. In the last orbit it has only six electrons. So, it requires 2 electrons to complete its octet. Therefore, it share 2 electrons with two hydrogen atom and forms 2 covalent bond with it.
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