A) 4 and 2
B) 9 and 14
C) 14 and 9
D) 2 and 4
Correct Answer: D
Solution :
The bcc cell consists of 8 atoms at the comers and one atom at centre \[\therefore \] \[n=\left( 8\times \frac{1}{8} \right)+1=2\] The fee cell consists of 8 atoms at the eight corners and one atom at each of the six faces. This atom at the face is shared by two unit cells. \[\therefore \] \[n=8\times \frac{1}{8}+\left( 6\times \frac{1}{2} \right)=4\]
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