A) \[NaCl\]
B) \[CsF\]
C) \[NaI\]
D) \[{{K}_{2}}S\]
Correct Answer: D
Solution :
\[{{K}_{2}}S\]formed by\[{{K}^{+}}\]and\[{{S}^{2-}}\]ion. We know that atomic number of K is 19 and in\[{{K}^{+}}\]ion its atomic number would be 18, similarly atomic number of S is 16 and in form\[{{S}^{2-}}\]ion its atomic number would be 18 so, the\[{{K}^{+}}\]and \[{{S}^{2-}}\]are isoelectronic with each other in\[{{K}_{2}}S\].
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