A) 1.0
B) 1.5
C) 2.5
D) 3.5
Correct Answer: C
Solution :
\[CI{{O}_{2}}\xrightarrow{{}}C{{l}^{-}}\] \[Cl{{O}_{2}}+2{{H}_{2}}O+5{{e}^{-}}\xrightarrow{{}}C{{l}^{-}}+4O{{H}^{-}}\] \[{{H}_{2}}{{O}_{2}}\xrightarrow{{}}{{O}_{2}}\] \[{{H}_{2}}{{O}_{2}}+2O{{H}^{-}}\xrightarrow{{}}{{O}_{2}}+2{{H}_{2}}O+2{{e}^{-}}\] \[Cl{{O}_{2}}+2{{H}_{2}}O+2{{e}^{-}}\xrightarrow{{}}C{{l}^{-}}+4O{{H}^{-}}]\times 2\] \[\begin{align} & \underline{\,\,\,\,\,\,\,\,\,\,\,{{H}_{2}}{{O}_{2}}+2O{{H}^{-}}\xrightarrow{{}}{{O}_{2}}+2{{H}_{2}}O+2{{e}^{-}}]\times 2\,\,\,\,\,\,\,\,\,\,} \\ & 2Cl{{O}_{2}}+5{{H}_{2}}{{O}_{2}}+2O{{H}^{-}}\xrightarrow{{}}2C{{l}^{-}}+5{{O}_{2}}+5{{H}_{2}}O \\ \end{align}\] \[2Cl{{O}_{2}}\equiv 5{{H}_{2}}{{O}_{2}}\] \[Cl{{O}_{2}}\equiv 2.5{{H}_{2}}{{O}_{2}}\]
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