A) Fehling solution
B) phenyl hydrazine
C) Benedict solution
D) hydroxylamine
Correct Answer: B
Solution :
\[\underset{\begin{smallmatrix} | \\ C{{H}_{2}}OH \end{smallmatrix}}{\overset{\begin{align} & CHO \\ & | \\ & CHOH \\ & | \\ \end{align}}{\mathop{{{(CHOH)}_{3}}}}}\,\xrightarrow[warm]{N{{H}_{2}}NH{{C}_{6}}{{H}_{5}}}\underset{\begin{align} & | \\ & C{{H}_{2}}OH \\ & \,\,\,Glucose \\ & phenyl\text{ }hydrazone \\ \end{align}}{\overset{\begin{align} & CH=N-NH{{C}_{6}}{{H}_{5}} \\ & | \\ & CHOH \\ & | \\ \end{align}}{\mathop{{{(CHOH)}_{3}}}}}\,\] \[\xrightarrow[{}]{N{{H}_{2}}NH{{C}_{6}}{{H}_{5}}}\underset{\begin{smallmatrix} | \\ C{{H}_{2}}OH \end{smallmatrix}}{\overset{\begin{align} & CH=N-NH{{C}_{6}}{{H}_{5}} \\ & | \\ & C=O \\ & | \\ \end{align}}{\mathop{{{(CHOH)}_{3}}}}}\,\] \[\xrightarrow[{}]{N{{H}_{2}}NH{{C}_{6}}{{H}_{5}}}\underset{\begin{smallmatrix} | \\ C{{H}_{2}}OH \\ glu\cos azone \end{smallmatrix}}{\overset{\begin{align} & CH=N-NH{{C}_{6}}{{H}_{5}} \\ & | \\ & C=N-NH{{C}_{6}}{{H}_{5}} \\ & | \\ \end{align}}{\mathop{{{(CHOH)}_{3}}}}}\,\] \[+{{C}_{6}}{{H}_{5}}N{{H}_{2}}+N{{H}_{3}}\]
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