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BHU PMT BHU PMT (Screening) Solved Paper-2006

  • question_answer
    The volume of a gas decreases from 500 cc to 300 cc when a sample gas is compressed by an average pressure of 0.6 atm. During this process 10 J of heat is liberated. The change in internal energy is:

    A)  \[-2.16J\]                           

    B) \[12.156\text{ }J\]

    C)   \[2.16J\]                            

    D) \[101.3\text{ }J\]

    Correct Answer: C

    Solution :

                     Here: change in volume \[(V)=500-300=200\text{ }cc=0.2\text{ }L\] Pressure (P)=0.6 atm and heat liberated \[(q)=10\,J\] Work done \[(W)=P\Delta V=(0.2\times 0.6)=0.12L-\text{ }atm\] But \[1\text{ }L-atm=101.3\text{ }J\] Hence, work\[=0.12\times 101.3=12.156\text{ }J\]. We also know that heat is liberated. Therefore, it would be negative. Thus, change in energy \[\Delta E=q+W=-10+12.16=2.16\,J\]


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